Adult comedy > Relationships, Mathematics >
let f(a) = \sqrt[n]{e^x}
\)
---
\(\begin{align}
& \lim_{t\to\infty} & f(a) & - \frac{i}{f(t)} & = \frac{d}{dx} f(u) \\
& \lim_{t\to\infty} & f(a) & - \frac{i}{\infty} & = \frac{d}{dx} f(u) \\
& \lim_{t\to\infty} & f(a) & - 0 & = \frac{d}{dx} f(u) \\
\end{align}
\) \(
\rightarrow
\) \(
\begin{align}
&& \sqrt[ n ]{e^x} & = \frac{d}{dx} f(u) \\
&& ( \sqrt[ n ]{e^x} )^n & = \frac{d}{dx} f(u)^n \\
&& e^x & = \frac{d}{dx} f(u)^n \\
&& \int{e^x} & = \int{ \frac{d}{dx} f(u)^n } \\
&& \int{e^x} & = \boxed{ f(u)^n }
\end{align}
\)
